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Surface area and surface integrals. (Sect. 16.5)
◮ Review: Arc length and line integrals.
◮ Review: Double integral of a scalar function.
◮ Explicit, implicit, parametric equations of surfaces.
◮ The area of a surface in space.
◮ The surface is given in parametric form.
◮ The surface is given in explicit form.
Review: Arc length and line integrals
◮ The integral of a function f : [a,b] → R is
Z b n
f (x)dx = lim Xf(x∗)∆x.
n→∞ i
a i=0
◮ The arc length of a curve r : [t0,t1] → R3 in space is
Z t
1 ′
st ,t = |r (t)|dt.
1 0
t
0
◮ The integral of a function f : R3 → R along a curve
Z Z t
1 ′
r : [t0, t1] → R3 is f ds = f r(t) |r (t)|dt.
C t
0
◮ The circulation of a function F : R3 → R3 along a curve
Z Z t
1 ′
r : [t0, t1] → R3 is F·uds = F r(t) ·r (t)dt.
C t
0
◮ The flux of a function F : {z = 0}∩R3 → {z = 0}∩R3 along
a loop r : [t0,t1] → {z = 0} ∩ R3 is F = I F · nds.
C
Surface area and surface integrals. (Sect. 16.5)
◮ Review: Arc length and line integrals.
◮ Review: Double integral of a scalar function.
◮ Explicit, implicit, parametric equations of surfaces.
◮ The area of a surface in space.
◮ The surface is given in parametric form.
◮ The surface is given in explicit form.
Review: Double integral of a scalar function
◮ The double integral of a function f : R ⊂ R2 → R on a region
R ⊂R2, which is the volume under the graph of f and above
the z = 0 plane, and is given by
ZZ n n
f dA = lim XXf(x∗,y∗)∆x∆y.
n→∞ i j
R i=0 j=0
◮ The area of a flat surface R ⊂ R2 is the particular case f = 1,
that is, A(R) = ZZ dA.
R
Wewill show how to compute:
◮ The area of a non-flat surface in space. (Today.)
◮ The integral of a scalar function f on a surface is space.
◮ The flux of a vector-valued function F on a surface in space.
Surface area and surface integrals. (Sect. 16.5)
◮ Review: Arc length and line integrals.
◮ Review: Double integral of a scalar function.
◮ Explicit, implicit, parametric equations of surfaces.
◮ The area of a surface in space.
◮ The surface is given in parametric form.
◮ The surface is given in explicit form.
Explicit, implicit, parametric equations of surfaces
Review: Curves on R2 can be defined in:
◮ Explicit form, y = f (x);
◮ Implicit form, F(x,y) = 0;
◮ Parametric form, r(t) = hx(t),y(t)i.
The vector r′(t) = hx′(t),y′(t)i is tangent to the curve.
Review: Surfaces in R3 can be defined in:
◮ Explicit form, z = f (x,y);
◮ Implicit form, F(x,y,z) = 0;
◮ Parametric form, r(u,v) = hx(u,v),y(u,v),z(u,v)i.
Two vectors tangent to the surface are
∂ r(u,v) = h∂ x(u,v),∂ y(u,v),∂ z(u,v)i,
u u u u
∂ r(u,v) = h∂ x(u,v),∂ y(u,v),∂ z(u,v)i.
v v v v
Explicit, implicit, parametric equations of surfaces
Example p
Find a parametric expression for the cone z = x2 +y2, and two
tangent vectors.
Solution: Use cylindrical coordinates: x = r cos(θ), y = r sin(θ),
z = z. Parameters of the surface: u = r, v = θ. Then
x(r,θ) = r cos(θ), y(r,θ) = r sin(θ), z(r,θ) = r.
Using vector notation, a parametric equation of the cone is
r(r,θ) = hr cos(θ),r sin(θ),ri.
Two tangent vectors to the cone are ∂ r and ∂ r,
r θ
∂ r = hcos(θ),sin(θ),1i, ∂ r = h−r sin(θ),r cos(θ),0i.
r θ ⊳
Explicit, implicit, parametric equations of surfaces
Example
Find a parametric expression for the sphere x2 + y2 + z2 = R2,
and two tangent vectors.
Solution: Use spherical coordinates:
x = ρcos(θ)sin(φ), y = ρsin(θ)sin(φ), z = ρcos(φ).
Parameters of the surface: u = θ, v = φ.
x = Rcos(θ)sin(φ), y = Rsin(θ)sin(φ), z = Rcos(φ).
Using vector notation, a parametric equation of the cone is
r(θ,φ) = R hcos(θ)sin(φ), sin(θ)sin(φ), cos(φ)i.
Two tangent vectors to the paraboloid are ∂ r and ∂ r,
θ φ
∂ r = R h−sin(θ)sin(φ), cos(θ)sin(φ), 0i,
θ
∂φr = R hcos(θ)cos(φ), sin(θ)cos(φ), −sin(φ)i. ⊳
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