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21. Chain rule Chain rule
Statement
21.1. Statement Examples
The power rule says that
d n n−1
dx [x ] = nx .
This rule is valid for any power n, but not for any base other than the simple input variable
x. For instance,
d 3 2
dx (2x+5) 6=3(2x+5) .
3 Table of Contents
The function h(x) = (2x + 5) is built up of the two simpler functions g(x) = 2x + 5 and
f(x) = x3:
3 3
h(x) = (2x+5) = (g(x)) = f(g(x)). ◭◭ ◮◮
Technically speaking, h is the composition of f and g. The next rule expresses the derivative
of such a function in terms of the derivatives of its components. ◭ ◮
Chain rule. For functions f and g Page 1 of 8
d [f(g(x))] = f′(g(x)) · g′(x).
dx Back
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In the composition f(g(x)), we call f the outside function and g the inside function. With
this terminology, the rule says that the derivative of the composition of two functions is Home Page
the derivative of the outside function evaluated at the inside function times the derivative
of the inside function.
21.2. Examples Chain rule
d Statement
21.2.1 Example Find the derivative (2x+5)3 .
dx Examples
3
Solution Webegin by viewing (2x+5) as a composition of functions and identifying the
outside function f and the inside function g. The outside function is the last thing you
do when computing the expression for a given input x. Here, the outside function is the
cubing function:
3 3
(2x+5) =f(g(x)), where f(x) = x and g(x)=2x+5.
Next, we do the computations required for the chain rule formula: Table of Contents
3
f(x) = x g(x) = 2x+5
f′(x) = 3x2 g′(x) = 2 ◭◭ ◮◮
f′(g(x)) = 3(2x+5)2 ◭ ◮
Finally, we use the formula:
d Page 2 of 8
dx [f(g(x))] = f′(g(x)) · g′(x)
↓ ↓ ↓ Back
d 3 2
dx (2x+5) = 3(2x+5) · 2 Print Version
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d 5
21.2.2 Example Find the derivative dx sin(x ) .
Solution Here, the outside function is the sine function: Chain rule
sin(x5) = f(g(x)), where f(x) = sinx and g(x) = x5. Statement
Examples
So
f(x) = sinx g(x) = x5
f′(x) = cosx g′(x) = 5x4
f′(g(x)) = cos(x5)
giving
d [f(g(x))] = f′(g(x)) · g′(x)
dx Table of Contents
d ↓ ↓ ↓
sin(x5) = cos(x5) · 5x4 ◭◭ ◮◮
dx
◭ ◮
d 5
21.2.3 Example Find the derivative sin x .
dx Page 3 of 8
Solution Recalling that sin5 x means (sinx)5, we see that the outside function is the one
that raises an input to the fifth power: Back
5 5 Print Version
sin x = f(g(x)), where f(x) = x and g(x)=sinx.
In order to reduce the number of steps, we go immediately to the chain rule formula and Home Page
do the intermediate computations mentally as required:
d [f(g(x))] = f′(g(x)) · g′(x) Chain rule
dx
d ↓ ↓ ↓ Statement
sin5 x = 5(sinx)4 · cosx Examples
dx
d h 2 i
21.2.4 Example Find the derivative dx 5x −4x+3 .
Solution Here, the outside function is the exponential function with base 5:
x2−4x+3 x 2 Table of Contents
5 =f(g(x)), where f(x) = 5 and g(x)=x −4x+3.
Trimming the number of steps a bit more, we omit the formula for the chain rule and ◭◭ ◮◮
just think “Derivative of outside function, evaluated at inside function, times derivative of
inside function”: h i
d 2 2 ◭ ◮
x −4x+3 x −4x+3
dx 5 =5 ln5·(2x−4).
Page 4 of 8
d √ x 3
21.2.5 Example Find the derivative dx 5e +4x .
Back
Solution The outside function is the square root function:
Print Version
h i
d p x 3 1 x 3 −1/2 x 2
dx 5e +4x = 2(5e +4x ) (5e +12x ).
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