257x Filetype PPTX File size 0.09 MB Source: abu.edu.iq
Order of reaction
It is the no of atoms or molecules whose concentration determine the rate of
reaction.
n A+n B+n C products
1 2 3
Rate =
Order = n + n + n
1 2 3
Reactions may be also classified according to molecularity.
Factors affecting rate of reaction
• Temperature.
• Catalysts.
• Conc. .
Half-time : the period of time required for a drug to decompose to one half the
original concentration .
Shelf time : time required for a drug to loss 10% of its original concentration .
Experimental work
Determination of specific reaction rate ethyl
acetate in presence of 1N HCL
Procedures:
1. In a dry clean stopped conical flask put 18 C.C. dist H2O
and 20 ml 1 N HCL.
2. To this mixture, add 2 C.C. ethyl acetate.
3. In another flask (titration flask) put 30 C.C. dist. H2O (by a
measure) and transfer 5 ml of the mixture into the
titration flask (use pepett) (water is added to decrease the
effect of ethyl acetate).
4. Titrate against 4N NaOH using Ph.Ph. indicator at 0 time or
blank E.P. = HCL.
5. i.e. E.P.o = b = HCL
6. Repeat the titiation after different time intervals:
5,15,30,40,50.
Calculation:
CH COOEt + H O CH COOH + EtOH
3 2 3
This is first order bimolecular reaction.
At 0 time: CH3COOEt is not affected.
So E.P. = HCL (blank, b.)
After 5:
E.P. = HCL + CH COOH (formed by hydrolysis or degradation)
3
E.P. after 5 – b. = HAc
= ml of NaOH equivalent to Hac
= ml of NaOH equivalent to decomposed ethyl acetate after 5 min.
(N * V- b) = (N * V) (= no. of mols of Ac presence in the sample)
NaOH EtAc
1n NaOH = 1n HAC = 1n Et Ac ( V = 5 ml)
EtAc
N = M
W = no. of mols * 88 (gm/mol Et Ac)
2
W 1(first used) = d * V (2 ml) Et Ac
W remaining in solution = W1 – W2
% Percentage remaining = [(W – W ) / (W + W )] * 100
1 2 1 2
And so a calculation is performed at other time intervals
The results are written in a table:
Log % remaining Percentage E.P Time
remaining
0
5
15
30
40
50
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